What is the critical f(x)= x/(\sqrt[3]{x^2-1)} ?

The critical f(x)= x/(\sqrt[3]{x^2-1)} is x=-sqrt(3),x=sqrt(3)

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critical f(x)= x/(\sqrt[3]{x^2-1)}

critical points

x = - 3, x = 3

Solution steps

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = 3, x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

is not defined at

x = - 1, x = 1

, therefore:

x = - 3, x = 3

f (x) = 3 x^{3} - 3 x^{2} - 3 x - 1

f (x) = 2 x^{3} + 3 x^{2} - 36 x + 5

f (x) = 2 x^{3} + 3 x^{2} - 36 x + 4

3 x^{4} - 4 x^{3} - 12 x + 1

f (x) = \frac{( 2 x - 1 )}{x ^{2} - 4 x - 5}

What is the critical f(x)= x/(\sqrt[3]{x^2-1)} ?
The critical f(x)= x/(\sqrt[3]{x^2-1)} is x=-sqrt(3),x=sqrt(3)