What is the critical f(x)=(x^2-2)/((x+2)^2) ?

The critical f(x)=(x^2-2)/((x+2)^2) is x=-1

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critical f(x)=(x^2-2)/((x+2)^2)

critical points

f (x) = \frac{x ^{2} - 2}{( x + 2 ) ^{2}}

x = - 1

Solution steps

\frac{x ^{2} - 2}{( x + 2 ) ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = - 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 2}{( x + 2 ) ^{2}} : x < - 2 or x > - 2

\frac{x ^{2} - 2}{( x + 2 ) ^{2}}

is not defined at

x = - 2

, therefore:

x = - 1

- 4 x^{2} + 2 y^{2} - 2 x y

\frac{( x + 2 ) ^{2}}{x - 2}

f (x, y) = x^{2} + y^{2} + 10 x - 10 y + 4

f (x) = \frac{3 e ^{3 x}}{4 x - 16}

f (x) = (x - 4)^{\frac{2}{3}}

What is the critical f(x)=(x^2-2)/((x+2)^2) ?
The critical f(x)=(x^2-2)/((x+2)^2) is x=-1