What is the critical f(x)=(3e^{3x})/(4x-16) ?

The critical f(x)=(3e^{3x})/(4x-16) is x= 13/3

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critical f(x)=(3e^{3x})/(4x-16)

critical points

f (x) = \frac{3 e ^{3 x}}{4 x - 16}

x = \frac{13}{3}

Solution steps

\frac{3 e ^{3 x}}{4 x - 16}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{13}{3}, x = 4

Identify critical points not in

f (x)

domain

Domain of

\frac{3 e ^{3 x}}{4 x - 16} : x < 4 or x > 4

\frac{3 e ^{3 x}}{4 x - 16}

is not defined at

x = 4

, therefore:

x = \frac{13}{3}

f (x) = (x - 4)^{\frac{2}{3}}

7 x - 8 y + 2 x y - x^{2} + y^{3}

f (x) = 9 x + 6 x^{- 1}

2 x^{3} - 9 x^{2} - 24 x + 1

3 x^{4} + 4 x^{3} - 12 x^{2} + 10

What is the critical f(x)=(3e^{3x})/(4x-16) ?
The critical f(x)=(3e^{3x})/(4x-16) is x= 13/3