What is the critical y=(e^{2x})/(x+2) ?

The critical y=(e^{2x})/(x+2) is x=-3/2

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critical y=(e^{2x})/(x+2)

critical points

y = \frac{e ^{2 x}}{x + 2}

x = - \frac{3}{2}

Solution steps

\frac{e ^{2 x}}{x + 2}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{3}{2}, x = - 2

Identify critical points not in

f (x)

domain

Domain of

\frac{e ^{2 x}}{x + 2} : x < - 2 or x > - 2

\frac{e ^{2 x}}{x + 2}

is not defined at

x = - 2

, therefore:

x = - \frac{3}{2}

f (x) = - 8 x + 6 sin (x)

f (x, y) = x^{4} + y^{4} - 4 x y + 2

y = x^{3} - 6 x^{2} + 9 x - 2

y = 3 x \cdot e^{x}

f (x) = \frac{( x ^{2 - 1} )}{( 2 x + 1 )}