What is the critical (x^2-81)/(x^2-7x-144) ?

The critical (x^2-81)/(x^2-7x-144) is None

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critical (x^2-81)/(x^2-7x-144)

critical points

\frac{x ^{2} - 81}{x ^{2} - 7 x - 144}

None

Solution steps

\frac{x ^{2} - 81}{x ^{2} - 7 x - 144}

Find where

f^{'} (x)

is equal to zero or undefined

x = 16

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 81}{x ^{2} - 7 x - 144} : x < - 9 or - 9 < x < 16 or x > 16

\frac{x ^{2} - 81}{x ^{2} - 7 x - 144}

is not defined at

x = 16

, therefore:

None

f (x, y) = 2 x^{3} + y^{3} + 3 x^{2} - 3 y + 12 x - 4

f (x) = \frac{x ^{2} + 3 x - 40}{x + 1}

f (x) = (x + 8)^{\frac{2}{3}}

f (x) = \frac{( x + 3 )}{x ^{2} - 5 x + 6}

f (x) = x^{4} - \frac{3 x ^{2}}{2} - x + \frac{29}{16}

What is the critical (x^2-81)/(x^2-7x-144) ?
The critical (x^2-81)/(x^2-7x-144) is None