What is the critical f(x,y)=2y^3-6xy-x^2 ?

The critical f(x,y)=2y^3-6xy-x^2 is (0,0),(9,-3)

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critical f(x,y)=2y^3-6xy-x^2

critical points

f (x, y) = 2 y^{3} - 6 x y - x^{2}

(0, 0), (9, - 3)

Solution steps

2 y^{3} - 6 x y - x^{2}

Find where

\nabla f (x, y)

is equal to zero or undefined

(0, 0), (9, - 3)

F (x) = x^{\frac{4}{5}} (x - 6)^{2}

cos (6 x), 0 \leq x \leq \frac{π}{2}

\frac{2 x ^{2} + 5}{x ^{2} - 25}

f (x) = - 12 x - 12

\frac{ω ^{2} + 2 ω + 1}{3 ω - 5}

What is the critical f(x,y)=2y^3-6xy-x^2 ?
The critical f(x,y)=2y^3-6xy-x^2 is (0,0),(9,-3)