What is the asymptotes of f(x)=(4x-3)/(2x+1) ?

The asymptotes of f(x)=(4x-3)/(2x+1) is Vertical: x=-1/2 ,Horizontal: y=2

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asymptotes of f(x)=(4x-3)/(2x+1)

asymptotes

f (x) = \frac{4 x - 3}{2 x + 1}

Vertical : x = - \frac{1}{2}, Horizontal : y = 2

Solution steps

Vertical asymptotes of

\frac{4 x - 3}{2 x + 1} : x = - \frac{1}{2}

Horizontal Asymptotes of

\frac{4 x - 3}{2 x + 1} : y = 2

Slant Asymptotes of

\frac{4 x - 3}{2 x + 1} :

None

Vertical : x = - \frac{1}{2}, Horizontal : y = 2

y = \frac{2 x ^{2}}{1 - x ^{2}}

\frac{x ^{2} + x - 6}{x + 2}

f (x) = \frac{5 x - 15}{x ^{2} - 8 x + 15}

h (x) = \frac{x + 1}{x ^{2} - 16}

f (x) = \frac{x ^{2} + 16}{x ^{2} - 16}

What is the asymptotes of f(x)=(4x-3)/(2x+1) ?
The asymptotes of f(x)=(4x-3)/(2x+1) is Vertical: x=-1/2 ,Horizontal: y=2