What is the asymptotes of f(x)= 1/(x^2-2x-8) ?

The asymptotes of f(x)= 1/(x^2-2x-8) is Vertical: x=-2,x=4,Horizontal: y=0

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asymptotes of f(x)= 1/(x^2-2x-8)

asymptotes

f (x) = \frac{1}{x ^{2} - 2 x - 8}

Vertical : x = - 2, x = 4, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{1}{x ^{2} - 2 x - 8} : x = - 2, x = 4

Horizontal Asymptotes of

\frac{1}{x ^{2} - 2 x - 8} : y = 0

Slant Asymptotes of

\frac{1}{x ^{2} - 2 x - 8} :

None

Vertical : x = - 2, x = 4, Horizontal : y = 0

f (x) = \frac{( x ^{2} - 6 x - 1 )}{x + 3}

f (x) = \frac{4}{10 x ^{2} - 411}

f (x) = \frac{4}{x} + 1

f (x) = \frac{x ^{3} + x ^{2} + 3}{x ^{2} - 9}

f (x) = \frac{( x + 7 )}{( x + 3 ) ( x - 5 )}

What is the asymptotes of f(x)= 1/(x^2-2x-8) ?
The asymptotes of f(x)= 1/(x^2-2x-8) is Vertical: x=-2,x=4,Horizontal: y=0