What is the asymptotes of f(x)=arctan(e^{9x}+1) ?

The asymptotes of f(x)=arctan(e^{9x}+1) is Horizontal: y= pi/2 ,y= pi/4

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asymptotes of f(x)=arctan(e^{9x}+1)

asymptotes

f (x) = arctan (e^{9 x} + 1)

Horizontal : y = \frac{π}{2}, y = \frac{π}{4}

Solution steps

Vertical asymptotes of

arctan (e^{9 x} + 1) :

None

Horizontal Asymptotes of

arctan (e^{9 x} + 1) : y = \frac{π}{2}, y = \frac{π}{4}

Slant Asymptotes of

arctan (e^{9 x} + 1) :

None

Horizontal : y = \frac{π}{2}, y = \frac{π}{4}

lo g_{10} (\frac{1}{3} x)

f (x) = \frac{x ^{2} + x - 6}{x ^{2} - 9}

f (x) = \frac{2 - 3 x}{x ^{2} - 2 x - 15}

f (x) = \frac{- 6 x ^{2} - 5 x + 1}{2 x + 1}

f (x) = 3 + \frac{( 3 x + 2 )}{x}

What is the asymptotes of f(x)=arctan(e^{9x}+1) ?
The asymptotes of f(x)=arctan(e^{9x}+1) is Horizontal: y= pi/2 ,y= pi/4