What is the axis y=2x^2-5x+1 ?

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axis y=2x^2-5x+1

axis

y = 2 x^{2} - 5 x + 1

x = \frac{5}{4}

Solution steps

y = 2 x^{2} - 5 x + 1

Rewrite

y = 2 x^{2} - 5 x + 1

in the standard form

4 \cdot \frac{1}{8} (y - (- \frac{17}{8})) = (x - \frac{5}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{4}, - \frac{17}{8}), p = \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{5}{4}

y = 2 x^{2} - 5 x + 3

y = + x^{2} + 4 x + 7

y^{2} = 40 x

y = - x^{2} + 64 x - 292

y = - 45 x^{2} - 27 x + 2