What is the axis y=(x^2-16x+70)/2 ?

The axis y=(x^2-16x+70)/2 is x=8

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axis y=(x^2-16x+70)/2

axis

y = \frac{x ^{2} - 16 x + 70}{2}

x = 8

Solution steps

y = \frac{x ^{2} - 16 x + 70}{2}

Rewrite

y = \frac{x ^{2} - 16 x + 70}{2}

in the standard form

4 \cdot \frac{1}{2} (y - 3) = (x - 8)^{2}

Therefore parabola properties are:

(h, k) = (8, 3), p = \frac{1}{2}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 8

x = (2 y + 5) (y + 6)

y = x^{2} + 12 x + 43

y = (0.5 - x)^{2}

y = - x^{2} - 3 x + 4

y = (x - 2 + 5) (x - 2 - 5)