What is x^2+y^2-18x-6y-10=0 ?

The solution to x^2+y^2-18x-6y-10=0 is Circle with (a,b)=(9,3),r=10

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x^2+y^2-18x-6y-10=0

x^{2} + y^{2} - 18 x - 6 y - 10 = 0

(a, b) = (9, 3), r = 10

Solution steps

x^{2} + y^{2} - 18 x - 6 y - 10 = 0

Rewrite

x^{2} + y^{2} - 18 x - 6 y - 10 = 0

in the form of the standard circle equation

(x - 9)^{2} + (y - 3)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (9, 3), r = 10

3 x^{2} + 3 y^{2} + 30 x - 48 y + 123 = 0

(x + 3)^{2} + y^{2} = 25

(x + 3)^{2} + y^{2} = 81

x^{2} + y^{2} - 1 \geq 0

x^{2} = 1 - y^{2}

What is x^2+y^2-18x-6y-10=0 ?
The solution to x^2+y^2-18x-6y-10=0 is Circle with (a,b)=(9,3),r=10