What is (x-3)^2+(y-4)^2=9 ?

The solution to (x-3)^2+(y-4)^2=9 is Circle with (a,b)=(3,4),r=3

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(x-3)^2+(y-4)^2=9

(x - 3)^{2} + (y - 4)^{2} = 9

(a, b) = (3, 4), r = 3

Solution steps

(x - 3)^{2} + (y - 4)^{2} = 9

Rewrite

(x - 3)^{2} + (y - 4)^{2} = 9

in the form of the standard circle equation

(x - 3)^{2} + (y - 4)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (3, 4), r = 3

x^{2} + y^{2} - 6 x + 4 y - 36 = 0

(x - 2)^{2} + (y - 4)^{2} = 100

x^{2} - 6 x + y^{2} - 7 = 0

x^{2} + y^{2} - 9 x + 4 y - 127 = 0

(x - 5)^{2} + (y - 4)^{2} = 36

What is (x-3)^2+(y-4)^2=9 ?
The solution to (x-3)^2+(y-4)^2=9 is Circle with (a,b)=(3,4),r=3