What is (x-1)^2+(y-2)^2=3^2 ?

The solution to (x-1)^2+(y-2)^2=3^2 is Circle with (a,b)=(1,2),r=3

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(x-1)^2+(y-2)^2=3^2

(x - 1)^{2} + (y - 2)^{2} = 3^{2}

(a, b) = (1, 2), r = 3

Solution steps

(x - 1)^{2} + (y - 2)^{2} = 3^{2}

Rewrite

(x - 1)^{2} + (y - 2)^{2} = 3^{2}

in the form of the standard circle equation

(x - 1)^{2} + (y - 2)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (1, 2), r = 3

x^{2} + (y + \frac{3}{5})^{2} = 27

x^{2} + y^{2} - 8 x + 12 y + 45 = 0

x^{2} + y^{2} - 8 x + 8 y + 16 = 0

x^{2} + y^{2} + 10 x - 6 y = 2

x^{2} - 8 x + y^{2} + 2 y + 8 = 0

What is (x-1)^2+(y-2)^2=3^2 ?
The solution to (x-1)^2+(y-2)^2=3^2 is Circle with (a,b)=(1,2),r=3