What is x^2+(y+3/5)^2=27 ?

The solution to x^2+(y+3/5)^2=27 is Circle with (a,b)=(0,-3/5),r=sqrt(27)

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x^2+(y+3/5)^2=27

x^{2} + (y + \frac{3}{5})^{2} = 27

(a, b) = (0, - \frac{3}{5}), r = 27

Solution steps

x^{2} + (y + \frac{3}{5})^{2} = 27

Rewrite

x^{2} + (y + \frac{3}{5})^{2} = 27

in the form of the standard circle equation

(x - 0)^{2} + (y - (- \frac{3}{5}))^{2} = (27)^{2}

Therefore the circle properties are:

(a, b) = (0, - \frac{3}{5}), r = 27

x^{2} + y^{2} - 8 x + 12 y + 45 = 0

x^{2} + y^{2} - 8 x + 8 y + 16 = 0

x^{2} + y^{2} + 10 x - 6 y = 2

x^{2} - 8 x + y^{2} + 2 y + 8 = 0

2 x^{2} + 2 y^{2} - 12 x + 2 y + 1 = 0

What is x^2+(y+3/5)^2=27 ?
The solution to x^2+(y+3/5)^2=27 is Circle with (a,b)=(0,-3/5),r=sqrt(27)