What is x^2+y^2+10x-6y=2 ?

The solution to x^2+y^2+10x-6y=2 is Circle with (a,b)=(-5,3),r=6

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x^2+y^2+10x-6y=2

x^{2} + y^{2} + 10 x - 6 y = 2

(a, b) = (- 5, 3), r = 6

Solution steps

x^{2} + y^{2} + 10 x - 6 y = 2

Rewrite

x^{2} + y^{2} + 10 x - 6 y = 2

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 3)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 5, 3), r = 6

x^{2} - 8 x + y^{2} + 2 y + 8 = 0

2 x^{2} + 2 y^{2} - 12 x + 2 y + 1 = 0

4 x^{2} + 4 y^{2} + 20 x - 8 y + 9 = 0

\frac{1}{2} y^{2} = - \frac{1}{2} x^{2} + 12.5

(x - 2)^{2} + (y + 3)^{2} = 11

What is x^2+y^2+10x-6y=2 ?
The solution to x^2+y^2+10x-6y=2 is Circle with (a,b)=(-5,3),r=6