What is 2x^2+2y^2-12x+2y+1=0 ?

The solution to 2x^2+2y^2-12x+2y+1=0 is Circle with (a,b)=(3,-1/2),r=(sqrt(35))/2

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2x^2+2y^2-12x+2y+1=0

2 x^{2} + 2 y^{2} - 12 x + 2 y + 1 = 0

(a, b) = (3, - \frac{1}{2}), r = \frac{35}{2}

Solution steps

2 x^{2} + 2 y^{2} - 12 x + 2 y + 1 = 0

Rewrite

2 x^{2} + 2 y^{2} - 12 x + 2 y + 1 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - (- \frac{1}{2}))^{2} = (\frac{35}{2})^{2}

Therefore the circle properties are:

(a, b) = (3, - \frac{1}{2}), r = \frac{35}{2}

4 x^{2} + 4 y^{2} + 20 x - 8 y + 9 = 0

\frac{1}{2} y^{2} = - \frac{1}{2} x^{2} + 12.5

(x - 2)^{2} + (y + 3)^{2} = 11

x^{2} + y^{2} + 16 x - 14 y + 49 = 0

x^{2} + y^{2} + 2 x + 8 y - 19 = 0

What is 2x^2+2y^2-12x+2y+1=0 ?
The solution to 2x^2+2y^2-12x+2y+1=0 is Circle with (a,b)=(3,-1/2),r=(sqrt(35))/2