What is (x-2)^2+(y+3)^2=11 ?

The solution to (x-2)^2+(y+3)^2=11 is Circle with (a,b)=(2,-3),r=sqrt(11)

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(x-2)^2+(y+3)^2=11

(x - 2)^{2} + (y + 3)^{2} = 11

(a, b) = (2, - 3), r = 11

Solution steps

(x - 2)^{2} + (y + 3)^{2} = 11

Rewrite

(x - 2)^{2} + (y + 3)^{2} = 11

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 3))^{2} = (11)^{2}

Therefore the circle properties are:

(a, b) = (2, - 3), r = 11

x^{2} + y^{2} + 16 x - 14 y + 49 = 0

x^{2} + y^{2} + 2 x + 8 y - 19 = 0

5 x^{2} + 5 y^{2} - 2 x - 30 y + 42 = 0

2 x^{2} + 2 y^{2} + 6 x - 8 y = - 12

x^{2} + y^{2} = - 2 x

What is (x-2)^2+(y+3)^2=11 ?
The solution to (x-2)^2+(y+3)^2=11 is Circle with (a,b)=(2,-3),r=sqrt(11)