What is x^2+y^2+16x-14y+49=0 ?

The solution to x^2+y^2+16x-14y+49=0 is Circle with (a,b)=(-8,7),r=8

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x^2+y^2+16x-14y+49=0

x^{2} + y^{2} + 16 x - 14 y + 49 = 0

(a, b) = (- 8, 7), r = 8

Solution steps

x^{2} + y^{2} + 16 x - 14 y + 49 = 0

Rewrite

x^{2} + y^{2} + 16 x - 14 y + 49 = 0

in the form of the standard circle equation

(x - (- 8))^{2} + (y - 7)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (- 8, 7), r = 8

x^{2} + y^{2} + 2 x + 8 y - 19 = 0

5 x^{2} + 5 y^{2} - 2 x - 30 y + 42 = 0

2 x^{2} + 2 y^{2} + 6 x - 8 y = - 12

x^{2} + y^{2} = - 2 x

(x - 3)^{2} + (y - 2)^{2} = 3

What is x^2+y^2+16x-14y+49=0 ?
The solution to x^2+y^2+16x-14y+49=0 is Circle with (a,b)=(-8,7),r=8