What is (x-5)^2+(y-1)^2=4 ?

The solution to (x-5)^2+(y-1)^2=4 is Circle with (a,b)=(5,1),r=2

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(x-5)^2+(y-1)^2=4

(x - 5)^{2} + (y - 1)^{2} = 4

(a, b) = (5, 1), r = 2

Solution steps

(x - 5)^{2} + (y - 1)^{2} = 4

Rewrite

(x - 5)^{2} + (y - 1)^{2} = 4

in the form of the standard circle equation

(x - 5)^{2} + (y - 1)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (5, 1), r = 2

x^{2} + y^{2} - 8 x + 2 y - 24 = 0

x^{2} + y^{2} - 4 x - 2 y - 31 = 0

(x + 2)^{2} + (y - 1)^{2} = 3

(x + 4)^{2} + (y - 34)^{2} = 1

2 (x - 2)^{2} + 2 y^{2} = 2

What is (x-5)^2+(y-1)^2=4 ?
The solution to (x-5)^2+(y-1)^2=4 is Circle with (a,b)=(5,1),r=2