What is x^2+y^2-23/2 x+11/2-13/2 =0 ?

The solution to x^2+y^2-23/2 x+11/2-13/2 =0 is Circle with (a,b)=(23/4 ,0),r=(sqrt(545))/4

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x^2+y^2-23/2 x+11/2-13/2 =0

x^{2} + y^{2} - \frac{23}{2} x + \frac{11}{2} - \frac{13}{2} = 0

(a, b) = (\frac{23}{4}, 0), r = \frac{545}{4}

Solution steps

x^{2} + y^{2} - \frac{23}{2} x + \frac{11}{2} - \frac{13}{2} = 0

Rewrite

x^{2} + y^{2} - \frac{23}{2} x + \frac{11}{2} - \frac{13}{2} = 0

in the form of the standard circle equation

(x - \frac{23}{4})^{2} + (y - 0)^{2} = (\frac{545}{4})^{2}

Therefore the circle properties are:

(a, b) = (\frac{23}{4}, 0), r = \frac{545}{4}

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What is x^2+y^2-23/2 x+11/2-13/2 =0 ?
The solution to x^2+y^2-23/2 x+11/2-13/2 =0 is Circle with (a,b)=(23/4 ,0),r=(sqrt(545))/4