What is (x+5)^2+(y-8)^2=25 ?

The solution to (x+5)^2+(y-8)^2=25 is Circle with (a,b)=(-5,8),r=5

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(x+5)^2+(y-8)^2=25

(x + 5)^{2} + (y - 8)^{2} = 25

(a, b) = (- 5, 8), r = 5

Solution steps

(x + 5)^{2} + (y - 8)^{2} = 25

Rewrite

(x + 5)^{2} + (y - 8)^{2} = 25

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 8)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 5, 8), r = 5

x^{2} + y^{2} - 6 x - 8 y + 21 = 0

x^{2} + y^{2} - 6 x - 6 y + 2 = 0

x^{2} + y^{2} + x + y = 0

x^{2} + y^{2} - 8 x + 4 y - 29 = 0

x^{2} + y^{2} - 2 x - 8 y + 13 = 0

What is (x+5)^2+(y-8)^2=25 ?
The solution to (x+5)^2+(y-8)^2=25 is Circle with (a,b)=(-5,8),r=5