What is x^2+y^2-6x-8y+21=0 ?

The solution to x^2+y^2-6x-8y+21=0 is Circle with (a,b)=(3,4),r=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2-6x-8y+21=0

x^{2} + y^{2} - 6 x - 8 y + 21 = 0

(a, b) = (3, 4), r = 2

Solution steps

x^{2} + y^{2} - 6 x - 8 y + 21 = 0

Rewrite

x^{2} + y^{2} - 6 x - 8 y + 21 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - 4)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (3, 4), r = 2

x^{2} + y^{2} - 6 x - 6 y + 2 = 0

x^{2} + y^{2} + x + y = 0

x^{2} + y^{2} - 8 x + 4 y - 29 = 0

x^{2} + y^{2} - 2 x - 8 y + 13 = 0

x^{2} + y^{2} + 16 x - 16 y + 79 = 0

What is x^2+y^2-6x-8y+21=0 ?
The solution to x^2+y^2-6x-8y+21=0 is Circle with (a,b)=(3,4),r=2