What is x^2+y^2-2x-8y+13=0 ?

The solution to x^2+y^2-2x-8y+13=0 is Circle with (a,b)=(1,4),r=2

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x^2+y^2-2x-8y+13=0

x^{2} + y^{2} - 2 x - 8 y + 13 = 0

(a, b) = (1, 4), r = 2

Solution steps

x^{2} + y^{2} - 2 x - 8 y + 13 = 0

Rewrite

x^{2} + y^{2} - 2 x - 8 y + 13 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - 4)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (1, 4), r = 2

x^{2} + y^{2} + 16 x - 16 y + 79 = 0

x^{2} + y^{2} - 10 x + 4 y + 4 = 0

\frac{( y - 2 ) ^{2}}{9} + \frac{( x - \frac{1}{2} ) ^{2}}{9} = 1

x^{2} + y^{2} - 4 x + 10 y - 7 = 0

(x + 1)^{2} + (y + 1)^{2} = 100

What is x^2+y^2-2x-8y+13=0 ?
The solution to x^2+y^2-2x-8y+13=0 is Circle with (a,b)=(1,4),r=2