What is x^2+y^2+16x-16y+79=0 ?

The solution to x^2+y^2+16x-16y+79=0 is Circle with (a,b)=(-8,8),r=7

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x^2+y^2+16x-16y+79=0

x^{2} + y^{2} + 16 x - 16 y + 79 = 0

(a, b) = (- 8, 8), r = 7

Solution steps

x^{2} + y^{2} + 16 x - 16 y + 79 = 0

Rewrite

x^{2} + y^{2} + 16 x - 16 y + 79 = 0

in the form of the standard circle equation

(x - (- 8))^{2} + (y - 8)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (- 8, 8), r = 7

x^{2} + y^{2} - 10 x + 4 y + 4 = 0

\frac{( y - 2 ) ^{2}}{9} + \frac{( x - \frac{1}{2} ) ^{2}}{9} = 1

x^{2} + y^{2} - 4 x + 10 y - 7 = 0

(x + 1)^{2} + (y + 1)^{2} = 100

x^{2} + y^{2} = 250

What is x^2+y^2+16x-16y+79=0 ?
The solution to x^2+y^2+16x-16y+79=0 is Circle with (a,b)=(-8,8),r=7