What is (x+3)^2+(y+2)^2=9 ?

The solution to (x+3)^2+(y+2)^2=9 is Circle with (a,b)=(-3,-2),r=3

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(x+3)^2+(y+2)^2=9

(x + 3)^{2} + (y + 2)^{2} = 9

(a, b) = (- 3, - 2), r = 3

Solution steps

(x + 3)^{2} + (y + 2)^{2} = 9

Rewrite

(x + 3)^{2} + (y + 2)^{2} = 9

in the form of the standard circle equation

(x - (- 3))^{2} + (y - (- 2))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 3, - 2), r = 3

3 (x - 3)^{2} + 3 y^{2} = 12

x^{2} + y^{2} - 10 y + 16 = 0

x^{2} + y^{2} + 2 x - 2 y = 0

9 x^{2} + 54 x + 9 y^{2} - 6 y + 64 = 0

x^{2} + y^{2} - 6 x + 8 y + 9 = 0

What is (x+3)^2+(y+2)^2=9 ?
The solution to (x+3)^2+(y+2)^2=9 is Circle with (a,b)=(-3,-2),r=3