What is x^2+(y-4)^2= 5/3 ?

The solution to x^2+(y-4)^2= 5/3 is Circle with (a,b)=(0,4),r=sqrt(5/3)

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x^2+(y-4)^2= 5/3

x^{2} + (y - 4)^{2} = \frac{5}{3}

(a, b) = (0, 4), r = \frac{5}{3}

Solution steps

x^{2} + (y - 4)^{2} = \frac{5}{3}

Rewrite

x^{2} + (y - 4)^{2} = \frac{5}{3}

in the form of the standard circle equation

(x - 0)^{2} + (y - 4)^{2} = (\frac{5}{3})^{2}

Therefore the circle properties are:

(a, b) = (0, 4), r = \frac{5}{3}

x^{2} + y^{2} + 3 x + 6 y + 9 = 0

(x - 2)^{2} + (y - 3)^{2} = 10

9 x^{2} + 9 y^{2} = 64

(x - 2)^{2} + (y - 3)^{2} = 49

4 x^{2} + 4 y^{2} + 16 x - 12 y + 1 = 0

What is x^2+(y-4)^2= 5/3 ?
The solution to x^2+(y-4)^2= 5/3 is Circle with (a,b)=(0,4),r=sqrt(5/3)