What is x^2+y^2+5x-y-1=0 ?

The solution to x^2+y^2+5x-y-1=0 is Circle with (a,b)=(-5/2 , 1/2),r=sqrt(15/2)

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x^2+y^2+5x-y-1=0

x^{2} + y^{2} + 5 x - y - 1 = 0

(a, b) = (- \frac{5}{2}, \frac{1}{2}), r = \frac{15}{2}

Solution steps

x^{2} + y^{2} + 5 x - y - 1 = 0

Rewrite

x^{2} + y^{2} + 5 x - y - 1 = 0

in the form of the standard circle equation

(x - (- \frac{5}{2}))^{2} + (y - \frac{1}{2})^{2} = (\frac{15}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{5}{2}, \frac{1}{2}), r = \frac{15}{2}

x^{2} + 8 x + y^{2} + 6 y = 0

x^{2} + y^{2} - 4 x - 3 y + 6 = 0

(X - 2)^{2} + (Y + 4)^{2} = 4

x^{2} + y^{2} + 2 x - 10 y + 22 = 0

(x + 2)^{2} + (y + 3)^{2} = 5

What is x^2+y^2+5x-y-1=0 ?
The solution to x^2+y^2+5x-y-1=0 is Circle with (a,b)=(-5/2 , 1/2),r=sqrt(15/2)