What is x^2+y^2+6x+2y-26=0 ?

The solution to x^2+y^2+6x+2y-26=0 is Circle with (a,b)=(-3,-1),r=6

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x^2+y^2+6x+2y-26=0

x^{2} + y^{2} + 6 x + 2 y - 26 = 0

(a, b) = (- 3, - 1), r = 6

Solution steps

x^{2} + y^{2} + 6 x + 2 y - 26 = 0

Rewrite

x^{2} + y^{2} + 6 x + 2 y - 26 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - (- 1))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 3, - 1), r = 6

(x - 9)^{2} + (y + 7)^{2} = 169

x^{2} + y^{2} \leq 5

3 x^{2} + 4 x + 3 y^{2} - 2 y = 0

(x - 2)^{2} + (y - 1)^{2} = 5^{2}

\frac{( x + 2 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1

What is x^2+y^2+6x+2y-26=0 ?
The solution to x^2+y^2+6x+2y-26=0 is Circle with (a,b)=(-3,-1),r=6