What is (x-5)^2+(y+6)^2=25 ?

The solution to (x-5)^2+(y+6)^2=25 is Circle with (a,b)=(5,-6),r=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-5)^2+(y+6)^2=25

(x - 5)^{2} + (y + 6)^{2} = 25

(a, b) = (5, - 6), r = 5

Solution steps

(x - 5)^{2} + (y + 6)^{2} = 25

Rewrite

(x - 5)^{2} + (y + 6)^{2} = 25

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 6))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (5, - 6), r = 5

x^{2} + y^{2} + 6 x + 2 y - 26 = 0

(x - 9)^{2} + (y + 7)^{2} = 169

x^{2} + y^{2} \leq 5

3 x^{2} + 4 x + 3 y^{2} - 2 y = 0

(x - 2)^{2} + (y - 1)^{2} = 5^{2}

What is (x-5)^2+(y+6)^2=25 ?
The solution to (x-5)^2+(y+6)^2=25 is Circle with (a,b)=(5,-6),r=5