What is x^2+y^2-14x-12y+76=0 ?

The solution to x^2+y^2-14x-12y+76=0 is Circle with (a,b)=(7,6),r=3

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x^2+y^2-14x-12y+76=0

x^{2} + y^{2} - 14 x - 12 y + 76 = 0

(a, b) = (7, 6), r = 3

Solution steps

x^{2} + y^{2} - 14 x - 12 y + 76 = 0

Rewrite

x^{2} + y^{2} - 14 x - 12 y + 76 = 0

in the form of the standard circle equation

(x - 7)^{2} + (y - 6)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (7, 6), r = 3

\frac{( x - 3 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{4} = 4

8 x^{2} + 8 y^{2} - 32 x + 64 y - 376 = 0

4 x^{2} + 4 y^{2} - 4 x + 8 y + 1 = 0

(x + 3)^{2} + (y - \frac{4}{3})^{2} = 36

(x - 3)^{2} + (y - 5)^{2} = 4

What is x^2+y^2-14x-12y+76=0 ?
The solution to x^2+y^2-14x-12y+76=0 is Circle with (a,b)=(7,6),r=3