What is (x+3)^2+(y-4/3)^2=36 ?

The solution to (x+3)^2+(y-4/3)^2=36 is Circle with (a,b)=(-3, 4/3),r=6

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(x+3)^2+(y-4/3)^2=36

(x + 3)^{2} + (y - \frac{4}{3})^{2} = 36

(a, b) = (- 3, \frac{4}{3}), r = 6

Solution steps

(x + 3)^{2} + (y - \frac{4}{3})^{2} = 36

Rewrite

(x + 3)^{2} + (y - \frac{4}{3})^{2} = 36

in the form of the standard circle equation

(x - (- 3))^{2} + (y - \frac{4}{3})^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 3, \frac{4}{3}), r = 6

(x - 3)^{2} + (y - 5)^{2} = 4

(x - 1)^{2} + (y - 4)^{2} = 9

\frac{x ^{2}}{5} + \frac{y ^{2}}{5} = 53

x^{2} + y^{2} + 4 x + 8 y + 11 = 0

x^{2} + y^{2} + 4 x - 12 y = 0

What is (x+3)^2+(y-4/3)^2=36 ?
The solution to (x+3)^2+(y-4/3)^2=36 is Circle with (a,b)=(-3, 4/3),r=6