What is ((x-3)^2)/4+((y+2)^2)/4 =4 ?

The solution to ((x-3)^2)/4+((y+2)^2)/4 =4 is Circle with (a,b)=(3,-2),r=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-3)^2)/4+((y+2)^2)/4 =4

\frac{( x - 3 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{4} = 4

(a, b) = (3, - 2), r = 4

Solution steps

\frac{( x - 3 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{4} = 4

Rewrite

\frac{( x - 3 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{4} = 4

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 2))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (3, - 2), r = 4

8 x^{2} + 8 y^{2} - 32 x + 64 y - 376 = 0

4 x^{2} + 4 y^{2} - 4 x + 8 y + 1 = 0

(x + 3)^{2} + (y - \frac{4}{3})^{2} = 36

(x - 3)^{2} + (y - 5)^{2} = 4

(x - 1)^{2} + (y - 4)^{2} = 9

What is ((x-3)^2)/4+((y+2)^2)/4 =4 ?
The solution to ((x-3)^2)/4+((y+2)^2)/4 =4 is Circle with (a,b)=(3,-2),r=4