What is (x^2+4x+4)+(y^2-8y+16)=-9+4+16 ?

The solution to (x^2+4x+4)+(y^2-8y+16)=-9+4+16 is Circle with (a,b)=(-2,4),r=sqrt(11)

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(x^2+4x+4)+(y^2-8y+16)=-9+4+16

(x^{2} + 4 x + 4) + (y^{2} - 8 y + 16) = - 9 + 4 + 16

(a, b) = (- 2, 4), r = 11

Solution steps

x^{2} + 4 x + 4 + (y^{2} - 8 y + 16) = - 9 + 4 + 16

Rewrite

x^{2} + 4 x + 4 + (y^{2} - 8 y + 16) = - 9 + 4 + 16

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 4)^{2} = (11)^{2}

Therefore the circle properties are:

(a, b) = (- 2, 4), r = 11

(x - 20)^{2} + (y - 0.05)^{2} = 81

2 x^{2} + 2 y^{2} - 2 x + 18 y + 33 = 0

(x - 3)^{2} + (y + 4)^{2} = 2

(x - 9)^{2} + (y + 1)^{2} = 36

9 x^{2} + 9 y^{2} = 4

What is (x^2+4x+4)+(y^2-8y+16)=-9+4+16 ?
The solution to (x^2+4x+4)+(y^2-8y+16)=-9+4+16 is Circle with (a,b)=(-2,4),r=sqrt(11)