What is 2x^2+2y^2-2x+18y+33=0 ?

The solution to 2x^2+2y^2-2x+18y+33=0 is Circle with (a,b)=(1/2 ,-9/2),r=2

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2x^2+2y^2-2x+18y+33=0

2 x^{2} + 2 y^{2} - 2 x + 18 y + 33 = 0

(a, b) = (\frac{1}{2}, - \frac{9}{2}), r = 2

Solution steps

2 x^{2} + 2 y^{2} - 2 x + 18 y + 33 = 0

Rewrite

2 x^{2} + 2 y^{2} - 2 x + 18 y + 33 = 0

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - (- \frac{9}{2}))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, - \frac{9}{2}), r = 2

(x - 3)^{2} + (y + 4)^{2} = 2

(x - 9)^{2} + (y + 1)^{2} = 36

9 x^{2} + 9 y^{2} = 4

x^{2} + y^{2} = \frac{4}{9}

(x - 3)^{2} + (y - 8)^{2} = 5^{2}

What is 2x^2+2y^2-2x+18y+33=0 ?
The solution to 2x^2+2y^2-2x+18y+33=0 is Circle with (a,b)=(1/2 ,-9/2),r=2