What is (x-9)^2+(y+1)^2=36 ?

The solution to (x-9)^2+(y+1)^2=36 is Circle with (a,b)=(9,-1),r=6

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(x-9)^2+(y+1)^2=36

(x - 9)^{2} + (y + 1)^{2} = 36

(a, b) = (9, - 1), r = 6

Solution steps

(x - 9)^{2} + (y + 1)^{2} = 36

Rewrite

(x - 9)^{2} + (y + 1)^{2} = 36

in the form of the standard circle equation

(x - 9)^{2} + (y - (- 1))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (9, - 1), r = 6

9 x^{2} + 9 y^{2} = 4

x^{2} + y^{2} = \frac{4}{9}

(x - 3)^{2} + (y - 8)^{2} = 5^{2}

x^{2} + y^{2} + 2 x - 8 y + 13 = 0

(x - 3)^{2} + (y + 2)^{2} = 10

What is (x-9)^2+(y+1)^2=36 ?
The solution to (x-9)^2+(y+1)^2=36 is Circle with (a,b)=(9,-1),r=6