What is x^2+y^2= 4/9 ?

The solution to x^2+y^2= 4/9 is Circle with (a,b)=(0,0),r= 2/3

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x^2+y^2= 4/9

x^{2} + y^{2} = \frac{4}{9}

(a, b) = (0, 0), r = \frac{2}{3}

Solution steps

x^{2} + y^{2} = \frac{4}{9}

Rewrite

x^{2} + y^{2} = \frac{4}{9}

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (\frac{2}{3})^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = \frac{2}{3}

(x - 3)^{2} + (y - 8)^{2} = 5^{2}

x^{2} + y^{2} + 2 x - 8 y + 13 = 0

(x - 3)^{2} + (y + 2)^{2} = 10

16 - x^{2} - y^{2} > 0

(x - 2)^{2} + (y + 4)^{2} = 25

What is x^2+y^2= 4/9 ?
The solution to x^2+y^2= 4/9 is Circle with (a,b)=(0,0),r= 2/3