What is (x-3)^2+(y-8)^2=5^2 ?

The solution to (x-3)^2+(y-8)^2=5^2 is Circle with (a,b)=(3,8),r=5

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(x-3)^2+(y-8)^2=5^2

(x - 3)^{2} + (y - 8)^{2} = 5^{2}

(a, b) = (3, 8), r = 5

Solution steps

(x - 3)^{2} + (y - 8)^{2} = 5^{2}

Rewrite

(x - 3)^{2} + (y - 8)^{2} = 5^{2}

in the form of the standard circle equation

(x - 3)^{2} + (y - 8)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (3, 8), r = 5

x^{2} + y^{2} + 2 x - 8 y + 13 = 0

(x - 3)^{2} + (y + 2)^{2} = 10

16 - x^{2} - y^{2} > 0

(x - 2)^{2} + (y + 4)^{2} = 25

x = x^{2} + y^{2}

What is (x-3)^2+(y-8)^2=5^2 ?
The solution to (x-3)^2+(y-8)^2=5^2 is Circle with (a,b)=(3,8),r=5