What is (x-2)^2+(y+4)^2=25 ?

The solution to (x-2)^2+(y+4)^2=25 is Circle with (a,b)=(2,-4),r=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-2)^2+(y+4)^2=25

(x - 2)^{2} + (y + 4)^{2} = 25

(a, b) = (2, - 4), r = 5

Solution steps

(x - 2)^{2} + (y + 4)^{2} = 25

Rewrite

(x - 2)^{2} + (y + 4)^{2} = 25

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 4))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (2, - 4), r = 5

x = x^{2} + y^{2}

x^{2} + 10 x + y^{2} - 16 - 11 = 0

x^{2} + y^{2} + 10 x - 8 y = - 32

x^{2} - 2 x + y^{2} + 4 y - 20 = 0

(x + 1)^{2} + (y - 1)^{2} = 5

What is (x-2)^2+(y+4)^2=25 ?
The solution to (x-2)^2+(y+4)^2=25 is Circle with (a,b)=(2,-4),r=5