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Popular >

x=x^2+y^2

Solution

x = x^{2} + y^{2}

Solution

(a, b) = (\frac{1}{2}, 0), r = \frac{1}{2}

Solution steps

x = x^{2} + y^{2}

Rewrite

x = x^{2} + y^{2}

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - 0)^{2} = (\frac{1}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, 0), r = \frac{1}{2}

Popular Examples

x^2+10x+y^2-16-11=0

x^{2} + 10 x + y^{2} - 16 - 11 = 0

x^2+y^2+10x-8y=-32

x^{2} + y^{2} + 10 x - 8 y = - 32

x^2-2x+y^2+4y-20=0

x^{2} - 2 x + y^{2} + 4 y - 20 = 0

(x+1)^2+(y-1)^2=5

(x + 1)^{2} + (y - 1)^{2} = 5

4x^2+16x+15+4y^2+6y=0

4 x^{2} + 16 x + 15 + 4 y^{2} + 6 y = 0

Frequently Asked Questions (FAQ)

What is x=x^2+y^2 ?
The solution to x=x^2+y^2 is Circle with (a,b)=(1/2 ,0),r= 1/2