What is 3x^2+3y^2-6x+5y=0 ?

The solution to 3x^2+3y^2-6x+5y=0 is Circle with (a,b)=(1,-5/6),r=(sqrt(61))/6

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3x^2+3y^2-6x+5y=0

3 x^{2} + 3 y^{2} - 6 x + 5 y = 0

(a, b) = (1, - \frac{5}{6}), r = \frac{61}{6}

Solution steps

3 x^{2} + 3 y^{2} - 6 x + 5 y = 0

Rewrite

3 x^{2} + 3 y^{2} - 6 x + 5 y = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - (- \frac{5}{6}))^{2} = (\frac{61}{6})^{2}

Therefore the circle properties are:

(a, b) = (1, - \frac{5}{6}), r = \frac{61}{6}

x^{2} - 8 x + y^{2} - 20 = 0

16 x^{2} + 16 y^{2} + 16 x + 40 y - 7 = 0

(x - 1)^{2} + (y - 2)^{2} = 3

x^{2} + (y - 5)^{2} = 9

x^{2} + 8 y = - y^{2} + 6 x

What is 3x^2+3y^2-6x+5y=0 ?
The solution to 3x^2+3y^2-6x+5y=0 is Circle with (a,b)=(1,-5/6),r=(sqrt(61))/6