What is (x-2)^2+(y+1)^2=3 ?

The solution to (x-2)^2+(y+1)^2=3 is Circle with (a,b)=(2,-1),r=sqrt(3)

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(x-2)^2+(y+1)^2=3

(x - 2)^{2} + (y + 1)^{2} = 3

(a, b) = (2, - 1), r = 3

Solution steps

(x - 2)^{2} + (y + 1)^{2} = 3

Rewrite

(x - 2)^{2} + (y + 1)^{2} = 3

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 1))^{2} = (3)^{2}

Therefore the circle properties are:

(a, b) = (2, - 1), r = 3

x^{2} + y^{2} - 10 x + 6 y - 15 = 0

4 (x - 5)^{2} + 4 y^{2} = 64

3 x^{2} - 6 x + 3 y^{2} - 18 y - 78 = 0

x^{2} + y^{2} = 1^{2}

x^{2} + y^{2} = 22

What is (x-2)^2+(y+1)^2=3 ?
The solution to (x-2)^2+(y+1)^2=3 is Circle with (a,b)=(2,-1),r=sqrt(3)