What is x^2+y^2-3x+5y-1=0 ?

The solution to x^2+y^2-3x+5y-1=0 is Circle with (a,b)=(3/2 ,-5/2),r=sqrt(19/2)

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x^2+y^2-3x+5y-1=0

x^{2} + y^{2} - 3 x + 5 y - 1 = 0

(a, b) = (\frac{3}{2}, - \frac{5}{2}), r = \frac{19}{2}

Solution steps

x^{2} + y^{2} - 3 x + 5 y - 1 = 0

Rewrite

x^{2} + y^{2} - 3 x + 5 y - 1 = 0

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - (- \frac{5}{2}))^{2} = (\frac{19}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, - \frac{5}{2}), r = \frac{19}{2}

(x - 2)^{2} + (y - 2)^{2} = 8

(x - 2)^{2} + (y - 2)^{2} = 9

(x - 1)^{2} + (y - 3)^{2} = 13

x^{2} + y^{2} + 8 x - 12 y - 8 = 0

(x - 2)^{2} + (y + 2)^{2} = 16

What is x^2+y^2-3x+5y-1=0 ?
The solution to x^2+y^2-3x+5y-1=0 is Circle with (a,b)=(3/2 ,-5/2),r=sqrt(19/2)