What is (x-3)^2+(y-2)^2=3^2 ?

The solution to (x-3)^2+(y-2)^2=3^2 is Circle with (a,b)=(3,2),r=3

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(x-3)^2+(y-2)^2=3^2

(x - 3)^{2} + (y - 2)^{2} = 3^{2}

(a, b) = (3, 2), r = 3

Solution steps

(x - 3)^{2} + (y - 2)^{2} = 3^{2}

Rewrite

(x - 3)^{2} + (y - 2)^{2} = 3^{2}

in the form of the standard circle equation

(x - 3)^{2} + (y - 2)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (3, 2), r = 3

(x - 0)^{2} + (y - 0)^{2} = 4^{2}

(x + y) 2 = x^{2} + y^{2}

x^{2} + y^{2} + 3 x - 8 y + 18 = 0

x^{2} + y^{2} - 2 x + 28 y + 181 = 0

4 (x - 4)^{2} + 4 y^{2} = 4

What is (x-3)^2+(y-2)^2=3^2 ?
The solution to (x-3)^2+(y-2)^2=3^2 is Circle with (a,b)=(3,2),r=3