What is (x-1)^2+(y+6)^2=4 ?

The solution to (x-1)^2+(y+6)^2=4 is Circle with (a,b)=(1,-6),r=2

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(x-1)^2+(y+6)^2=4

(x - 1)^{2} + (y + 6)^{2} = 4

(a, b) = (1, - 6), r = 2

Solution steps

(x - 1)^{2} + (y + 6)^{2} = 4

Rewrite

(x - 1)^{2} + (y + 6)^{2} = 4

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 6))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (1, - 6), r = 2

x^{2} + y^{2} + 8 x - 6 y + 21 = 0

x^{2} + y^{2} - 2 x + 8 y - 47 = 0

(x - 4)^{2} + (y + 3)^{2} = 25

x^{2} + y^{2} - 6 x - 16 y + 24 = 0

x^{(2)} + y^{(2)} - 4 x - 6 y + 9 = 0

What is (x-1)^2+(y+6)^2=4 ?
The solution to (x-1)^2+(y+6)^2=4 is Circle with (a,b)=(1,-6),r=2