What is 5x^2+5y^2-7x+11y-9=0 ?

The solution to 5x^2+5y^2-7x+11y-9=0 is Circle with (a,b)=(7/10 ,-11/10),r=sqrt(7/2)

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5x^2+5y^2-7x+11y-9=0

5 x^{2} + 5 y^{2} - 7 x + 11 y - 9 = 0

(a, b) = (\frac{7}{10}, - \frac{11}{10}), r = \frac{7}{2}

Solution steps

5 x^{2} + 5 y^{2} - 7 x + 11 y - 9 = 0

Rewrite

5 x^{2} + 5 y^{2} - 7 x + 11 y - 9 = 0

in the form of the standard circle equation

(x - \frac{7}{10})^{2} + (y - (- \frac{11}{10}))^{2} = (\frac{7}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{7}{10}, - \frac{11}{10}), r = \frac{7}{2}

x^{2} + 10 x + y^{2} - 12 y = 3

x^{2} + y^{2} - 22 y - 5 = 0

x^{2} + y^{2} + 6 x + 8 y - 75 = 0

\frac{1}{2} x^{2} + \frac{1}{2} y^{2} = 16

(x - 5)^{2} + y^{2} = 38

What is 5x^2+5y^2-7x+11y-9=0 ?
The solution to 5x^2+5y^2-7x+11y-9=0 is Circle with (a,b)=(7/10 ,-11/10),r=sqrt(7/2)