What is x^2-6x+y^2-4y-12=0 ?

The solution to x^2-6x+y^2-4y-12=0 is Circle with (a,b)=(3,2),r=5

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x^2-6x+y^2-4y-12=0

x^{2} - 6 x + y^{2} - 4 y - 12 = 0

(a, b) = (3, 2), r = 5

Solution steps

x^{2} - 6 x + y^{2} - 4 y - 12 = 0

Rewrite

x^{2} - 6 x + y^{2} - 4 y - 12 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - 2)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (3, 2), r = 5

x^{2} + y^{2} - 4 x + 6 y = 0

x^{2} + y^{2} + 28 x + 52 = 0

3 x^{2} + 3 y^{2} - 12 y - 8 = 0

(x - 2)^{2} + (y - 4)^{2} = 4

- x^{2} - 6 x = z^{2} + 2 z + 1

What is x^2-6x+y^2-4y-12=0 ?
The solution to x^2-6x+y^2-4y-12=0 is Circle with (a,b)=(3,2),r=5