What is x^2+y^2+4x-6y+3=0 ?

The solution to x^2+y^2+4x-6y+3=0 is Circle with (a,b)=(-2,3),r=sqrt(10)

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x^2+y^2+4x-6y+3=0

x^{2} + y^{2} + 4 x - 6 y + 3 = 0

(a, b) = (- 2, 3), r = 10

Solution steps

x^{2} + y^{2} + 4 x - 6 y + 3 = 0

Rewrite

x^{2} + y^{2} + 4 x - 6 y + 3 = 0

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 3)^{2} = (10)^{2}

Therefore the circle properties are:

(a, b) = (- 2, 3), r = 10

(x - 13.4)^{2} + (y + 2.6)^{2} = 100

(x - 3)^{2} + (y + 5)^{2} = 36

x^{2} + y^{2} + 18 x + 4 y - 15 = 0

x^{2} + y^{2} + 2 x + 14 y - 31 = 0

x^{2} + 4 x + y^{2} - 8 y - 5 = 0

What is x^2+y^2+4x-6y+3=0 ?
The solution to x^2+y^2+4x-6y+3=0 is Circle with (a,b)=(-2,3),r=sqrt(10)