What is 1=(x-1)^2+(y+4)^2 ?

The solution to 1=(x-1)^2+(y+4)^2 is Circle with (a,b)=(1,-4),r=1

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1=(x-1)^2+(y+4)^2

1 = (x - 1)^{2} + (y + 4)^{2}

(a, b) = (1, - 4), r = 1

Solution steps

1 = (x - 1)^{2} + (y + 4)^{2}

Rewrite

1 = (x - 1)^{2} + (y + 4)^{2}

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 4))^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (1, - 4), r = 1

(x + 1)^{2} + (y - 5)^{2} = 20

x^{2} + y^{2} + 6 x - 8 y + 13 = 0

(x + 4)^{2} + (y - 5)^{2} = 4

4 x^{2} + 4 y^{2} - 16 x + 24 y - 12 = 0

x^{2} - 6 x + y^{2} - 20 y + 44 = 0

What is 1=(x-1)^2+(y+4)^2 ?
The solution to 1=(x-1)^2+(y+4)^2 is Circle with (a,b)=(1,-4),r=1