What is x^2-6x+y^2-20y+44=0 ?

The solution to x^2-6x+y^2-20y+44=0 is Circle with (a,b)=(3,10),r=sqrt(65)

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x^2-6x+y^2-20y+44=0

x^{2} - 6 x + y^{2} - 20 y + 44 = 0

(a, b) = (3, 10), r = 65

Solution steps

x^{2} - 6 x + y^{2} - 20 y + 44 = 0

Rewrite

x^{2} - 6 x + y^{2} - 20 y + 44 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - 10)^{2} = (65)^{2}

Therefore the circle properties are:

(a, b) = (3, 10), r = 65

x^{2} + y^{2} + 5 x - y - 2 = 0

x^{2} + y^{2} - 8 x - 20 y + 52 = 0

(x)^{2} + (y)^{2} = 1

(x - 2)^{2} + (y - 1)^{2} = 49

y^{2} + x^{2} \leq 1

What is x^2-6x+y^2-20y+44=0 ?
The solution to x^2-6x+y^2-20y+44=0 is Circle with (a,b)=(3,10),r=sqrt(65)